55t-16t^2=0

Solution for 55t-16t^2=0 equation:

55t-16t^2=0

a = -16; b = 55; c = 0;
Δ = b2-4ac
Δ = 552-4·(-16)·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-55}{2*-16}=\frac{-110}{-32}
=3+7/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+55}{2*-16}=\frac{0}{-32}
=0
$